电工技术作业答案
作业1答案
1-1
(发出)
(吸收)
(吸收)
(功率平衡)该支路吸收电能
1-2 (1)
(2)
(3)
1-3 (a)
(b)
1-4
1-5 S断开时
S闭合时
作业2答案
2-1
代入数据解方程可得,=,A
2-2
代入数据解方程可得-0.5A 3.5V
2-3 略
2-4 0A
2-5该电路中只有两个结点,选左边结点为参考结点,结点电压方程如下:
再根据KVL可得三个电流 A EMBED Equation.3 A EMBED Equation.3 A
2-6 将10 EMBED Equation.3 支路断开,左边回路电流为 EMBED Equation.3 EMBED Equation.3 右边回路电流为 EMBED Equation.3
EMBED Equation.3 EMBED Equation.3
EMBED Equation.3 EMBED Equation.3 EMBED Equation.3
2-7 (a) EMBED Equation.3 EMBED Equation.3
(b) EMBED Equation.3 EMBED Equation.3
作业3答案
3-1 EMBED Equation.3 EMBED Equation.3
EMBED Equation.3 EMBED Equation.3
3-2 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3
3-3 EMBED Equation.3 EMBED Equation.3
EMBED Equation.3 EMBED Equation.3 EMBED Equation.3
EMBED Equation.3 EMBED Equation.3
3-4 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3
EMBED Equation.3 EMBED Equation.3 EMBED Equation.3
3-5 EMBED Equation.3 EMBED Equation.3
EMBED Equation.3 EMBED Equation.3
3-6 EMBED Equation.3 EMBED Equation.3
3-7 EMBED Equation.3 EMBED Equation.3 =3.79 EMBED Equation.3
作业4答案
4-1 略
4-2 略
4-3 相电压: EMBED Equation.3 电流和线电流: EMBED Equation.3
4-4 (1)各相电流分别为: EMBED Equation.3 EMBED Equation.3 EMBED Equation.3
中线电流为三个相电流的和: EMBED Equation.3
(2) EMBED Equation.3 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3
(3)U相负载的电压和电流均为0,V相负载的电压为 EMBED Equation.3
V相负载和W相负载