【期末满分押题】 2021-2022学年七年级数学下册高频考点精选精练（苏科版） （含解析）.doc

试卷第页共页期末满分押题学年七年级数学下册高频考点精选精练苏科版含解析一单选题下列方程组中是二元一次方程组的是eqId58ff7f10e7f187a76a4940590e0f18e1eqId96386f4e7b90916faba24748bedc978beqId3d279c4d38bdf3c24fb7bb3b01073798eqId2b590c1ec25474084e7c2befe630b058运输吨化肥装载了节火车车厢和辆汽车运输吨化肥装载了节火车车厢和辆汽车则每节火车车厢每辆汽车平均各装化肥分别是吨吨吨吨吨吨吨吨计算eqIda42bf42c439a3db51fa35fbc9659bdfa的结果是eqId5f4e30d17d9b14aee33d1dc85813e5e9eqId8c0cab73c7bf9043c73e5c9fa1a29beaeqIde0ada81aa55f0aea6dbc065f5fb49316以上答案都不对下列运算正确的是eqId7a300687efa8aa228c6199aa34ba97e3eqIdcd92f70970d04be8c705726e3d3c9ccbeqId85aacb7d0fe21f39cf803b1c2339ced4eqId0dada131bd1f1a6e7c5a22af33bd9e3e已知eqId31d6b2aed95c73ca8effbaed07ed25e7是完全平方式则eqId294f5ba74cdf695fc9a8a8e52f421328的值为或某班有eqId81dea63b8ce3e51adf66cf7b9982a248人分eqIdd053b14c8588eee2acbbe44fc37a6886组活动若每组人则余下人每组人则有一组差人根据题意下列方程组正确的是eqId2ea141a44cf008d8197a2279cdd2ddd9eqId0e70e4ceee3bb2dd184125ddd058e900eqIdc9fd30b04fb478a9a625d7d464c83376eqIdaa191cd7bd073c7e1e1dcfb7cc315993用数轴表示不等式eqIde2fb40a36a293471742ce75f6b9635b8的解集正确的是若则下列不等式变形正确的是试卷第页共页eqIdc13b34c99b942b8dd2cbd88ed017de36下列运算正确的是eqId5b016f446b221306f9a6747551d50d27eqIdf5dee56ee1a1b543d6e59b6ef45c3676eqId705380f071e15d6c9f8f730679e8fecaeqId906ecab9202b8a7ba365a08f64d43e74将正六边形与正五边形按如图所示方式摆放公共顶点为且正六边形的边与正五边形的边在同一条直线上则的度数是二填空题已知eqId646e7381621094aff3af2f3b7aad31ac则eqId2d2f28d9948d2460eb17c8678ee6eebd若eqId4f8d30f2457f8f34c77789c46a890fbf是二元一次方程则eqIda80fc13f715f0d726aac0cd72ee00e66不等式的正整数解为方程组eqId64c46a8f3d1d26973e31571d5a8a749e的解适合方程则的值为已知能用完全平方公式因式分解则的值为含有三个相同的未知数每个方程中含未知数的项的次数都是并且一共有三个方程像这样的方程组叫做三解答题计算eqId7678e945c2a3d7644a1a082d5acb425deqIdbc9477036604431b2c3ed73e8454e358已知如图点eqId2a30f3a8b673cc28bd90c50cf1a35281在eqId60ef95894ceebaf236170e8832dcf7e3上且eqId805b701bf7a21677e0585ed598c7aa54求证eqId5f79863ffcfa63117ca6741b20a48e69运用乘法公式进行计算eqId1f1b9e504aab0e48270f4045262c2ec5试卷第页共页eqId13f960e729e3a21472c0d7c436143999矩形纸片的长和宽分别为eqId0a6936d370d6a238a608ca56f87198deeqId2c94bb12cee76221e13f9ef955b0aab1在纸片的四个角都剪去一个边长为eqId81dea63b8ce3e51adf66cf7b9982a248的正方形请画出图形并用含有eqId0a6936d370d6a238a608ca56f87198deeqId2c94bb12cee76221e13f9ef955b0aab1eqId81dea63b8ce3e51adf66cf7b9982a248的代数式表示纸片剩余部分的面积当eqIde9e3cbf7722cf5551f44a0f28cc9f84d剩余部分的面积恰好等于剪去面积的倍时求纸片的长与宽因式分解eqIde7d19a66c05ad18e2bcb2aeeb123b3f8eqId20fb2a34ffc436544fabd9c680cc1cdfeqId9bdeb728de462f780be96acc8a4def14计算eqId83c560c61e78fa0f9b3e99643f1a09c6eqId6caea7544056f84d6657f8929e3033af